Vizing's Conjecture

In graph theory, Vizing's conjecture concerns a relation between the domination number and the cartesian product of graphs.
This conjecture was first stated by , and states that, if denotes the minimum number of vertices in a dominating set for the graph , then

: $\gamma(G\,\Box\,H) \ge \gamma(G)\gamma(H). \,$

conjectured a similar bound for the domination number of the tensor product of graphs; however, a counterexample was found by . Since Vizing proposed his conjecture, many mathematicians have worked on it, with partial results described below. For a more detailed overview of these results, see .

Examples

A 4-cycle has domination number two: any single vertex only dominates itself and its two neighbors, but any pair of vertices dominates the whole graph. The product is a four-dimensional hypercube graph; it has 16 vertices, and any single vertex can only dominate itself and four neighbors, so three vertices could only dominate 15 of the 16 vertices. Therefore, at least four vertices are required to dominate the entire graph, the bound given by Vizing's conjecture.

It is possible for the domination number of a product to be much larger than the bound given by Vizing's conjecture. For instance, for a star , its domination number is one: it is possible to dominate the entire star with a single vertex at its hub. Therefore, for the graph formed as the product of two stars, Vizing's conjecture states only that the domination number should be at least . However, the domination number of this graph is actually much higher. It has vertices: formed from the product of a leaf in both factors, from the product of a leaf in one factor and the hub in the other factor, and one remaining vertex formed from the product of the two hubs. Each leaf-hub product vertex in dominates exactly of the leaf-leaf vertices, so leaf-hub vertices are needed to dominate all of the leaf-leaf vertices. However, no leaf-hub vertex dominates any other such vertex, so even after leaf-hub vertices are chosen to be included in the dominating set, there remain more undominated leaf-hub vertices, which can be dominated by the single hub-hub vertex. Thus, the domination number of this graph is far higher than the trivial bound of one given by Vizing's conjecture.

There exist infinite families of graph products for which the bound of Vizing's conjecture is exactly met. For instance, if and are both connected graphs, each having at least four vertices and having exactly twice as many total vertices as their domination numbers, then .. The graphs and with this property consist of the four-vertex cycle together with the rooted products of a connected graph and a single edge.

Partial results

Clearly, the conjecture holds when either or has domination number one: for, the product contains an isomorphic copy of the other factor, dominating which requires at least vertices.

Vizing's conjecture is also known to hold for cycles and for graphs with domination number two..

proved that the domination number of the product is at least half as large as the conjectured bound, for all and .

Upper bounds

observed that

: $\gamma(G \,\Box\, H) \le \min\.$

A dominating set meeting this bound may be formed as the cartesian product of a dominating set in one of ''G'' or ''H'' with the set of all vertices in the other graph.

Notes

References

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External links

*{{mathworld , title = Vizing Conjecture , urlname = VizingConjecture

Graph invariants
Graph products
Conjectures
Unsolved problems in graph theory