The
following inequality is known as Sedrakyan's inequality,
Bergström's inequality, Engel's form or Titu's lemma, respectively, referring to the article ''About the applications of one useful inequality'' of
Nairi Sedrakyan
Nairi Sedrakyan (born 1961 in Ninotsminda, USSR) is Erdős Award 2022 winner Armenian mathematician involved in national and international Olympiads, including American Mathematics Competitions (USA) and IMO, having been the president of the A ...
published in 1997,
to the book ''Problem-solving strategies'' of
Arthur Engel published in 1998 and to the book ''Mathematical Olympiad Treasures'' of
Titu Andreescu published in 2003.
It is a direct consequence of
Cauchy–Bunyakovsky–Schwarz inequality. Nevertheless, in his article (1997) Sedrakyan has noticed that written in this form this inequality can be used as a mathematical proof technique and it has very useful new applications. In the book ''Algebraic Inequalities'' (Sedrakyan) are provided several generalizations of this inequality.
Statement of the inequality
For any reals
and positive reals
we have
(
Nairi Sedrakyan
Nairi Sedrakyan (born 1961 in Ninotsminda, USSR) is Erdős Award 2022 winner Armenian mathematician involved in national and international Olympiads, including American Mathematics Competitions (USA) and IMO, having been the president of the A ...
(1997),
Arthur Engel (1998),
Titu Andreescu (2003))
Probabilistic statement
Similarly to the
Cauchy–Schwarz inequality
The Cauchy–Schwarz inequality (also called Cauchy–Bunyakovsky–Schwarz inequality) is considered one of the most important and widely used inequalities in mathematics.
The inequality for sums was published by . The corresponding inequality fo ...
, one can generalize Sedrakyan's inequality to
random variable
A random variable (also called random quantity, aleatory variable, or stochastic variable) is a mathematical formalization of a quantity or object which depends on random events. It is a mapping or a function from possible outcomes (e.g., the po ...
.
In this formulation let
be a real random variable, and let
be a positive random variable. ''X'' and ''Y'' need not be independent, but we assume
and
Direct applications
Example 1.
Nesbitt's inequality In mathematics, Nesbitt's inequality (mathematics), inequality states that for positive real numbers ''a'', ''b'' and ''c'',
:\frac+\frac+\frac\geq\frac.
It is an elementary special case (N = 3) of the difficult and much studied Shapiro inequality, ...
.
For positive real numbers
a, b, c:
\frac + \frac + \frac \geq \frac.
Example 2.
International Mathematical Olympiad
The International Mathematical Olympiad (IMO) is a mathematical olympiad for pre-university students, and is the oldest of the International Science Olympiads. The first IMO was held in Romania in 1959. It has since been held annually, except i ...
(IMO) 1995.
For positive real numbers
a,b,c , where
abc=1 we have that
\frac+\frac+\frac \geq \frac.
Example 3.
For positive real numbers
a,b we have that
8(a^4+b^4) \geq (a+b)^4.
Example 4.
For positive real numbers
a,b,c we have that
\frac+\frac+\frac \geq \frac.
Proofs
Example 1.
Proof: Use
n = 3, \left(a_1, a_2, a_3\right) := (a, b, c), and
\left(b_1, b_2, b_3\right) := (a(b + c), b(c + a), c(a + b)) to conclude:
\frac + \frac + \frac \geq \frac = \frac = \frac + 1 \geq \frac (1) + 1 = \frac. \blacksquare
Example 2.
We have that
\frac + \frac + \frac \geq \frac = \frac \geq \frac = \frac.
Example 3.
We have
\frac + \frac \geq \frac so that
a^4 + b^4 = \frac + \frac \geq \frac \geq \frac = \frac.
Example 4.
We have that
\frac + \frac + \frac \geq \frac = \frac.
References
{{DEFAULTSORT:Sedrakyan's inequality
Inequalities
Linear algebra
Operator theory
Articles containing proofs
Mathematical analysis
Probabilistic inequalities>X, /math> and
E /math> are both defined.
Then
\operatorname ^2/Y\ge \operatorname \ge_\operatorname 2___\operatorname <_math>
<h1><br>.html" ;"title="X, ]^2 / \operatorname \ge \operatorname 2 / \operatorname
Direct applications
Example 1. Nesbitt's inequality In mathematics, Nesbitt's inequality (mathematics), inequality states that for positive real numbers ''a'', ''b'' and ''c'',
:\frac+\frac+\frac\geq\frac.
It is an elementary special case (N = 3) of the difficult and much studied Shapiro inequality, ...
.
For positive real numbers a, b, c:
\frac + \frac + \frac \geq \frac.
Example 2. International Mathematical Olympiad
The International Mathematical Olympiad (IMO) is a mathematical olympiad for pre-university students, and is the oldest of the International Science Olympiads. The first IMO was held in Romania in 1959. It has since been held annually, except i ...
(IMO) 1995.
For positive real numbers a,b,c , where abc=1 we have that \frac+\frac+\frac \geq \frac.
Example 3.
For positive real numbers a,b we have that 8(a^4+b^4) \geq (a+b)^4.
Example 4.
For positive real numbers a,b,c we have that \frac+\frac+\frac \geq \frac.
Proofs
Example 1.
Proof: Use n = 3, \left(a_1, a_2, a_3\right) := (a, b, c), and \left(b_1, b_2, b_3\right) := (a(b + c), b(c + a), c(a + b)) to conclude: \frac + \frac + \frac \geq \frac = \frac = \frac + 1 \geq \frac (1) + 1 = \frac. \blacksquare
Example 2.
We have that \frac + \frac + \frac \geq \frac = \frac \geq \frac = \frac.
Example 3.
We have \frac + \frac \geq \frac so that a^4 + b^4 = \frac + \frac \geq \frac \geq \frac = \frac.
Example 4.
We have that \frac + \frac + \frac \geq \frac = \frac.
References
{{DEFAULTSORT:Sedrakyan's inequality
Inequalities
Linear algebra
Operator theory
Articles containing proofs
Mathematical analysis
Probabilistic inequalities>X, /math> and E /math> are both defined.
Then
\operatorname ^2/Y\ge \operatorname \ge \operatorname 2 / \operatorname
Direct applications
Example 1. Nesbitt's inequality In mathematics, Nesbitt's inequality (mathematics), inequality states that for positive real numbers ''a'', ''b'' and ''c'',
:\frac+\frac+\frac\geq\frac.
It is an elementary special case (N = 3) of the difficult and much studied Shapiro inequality, ...
.
For positive real numbers a, b, c:
\frac + \frac + \frac \geq \frac.
Example 2. International Mathematical Olympiad
The International Mathematical Olympiad (IMO) is a mathematical olympiad for pre-university students, and is the oldest of the International Science Olympiads. The first IMO was held in Romania in 1959. It has since been held annually, except i ...
(IMO) 1995.
For positive real numbers a,b,c , where abc=1 we have that \frac+\frac+\frac \geq \frac.
Example 3.
For positive real numbers a,b we have that 8(a^4+b^4) \geq (a+b)^4.
Example 4.
For positive real numbers a,b,c we have that \frac+\frac+\frac \geq \frac.
Proofs
Example 1.
Proof: Use n = 3, \left(a_1, a_2, a_3\right) := (a, b, c), and \left(b_1, b_2, b_3\right) := (a(b + c), b(c + a), c(a + b)) to conclude: \frac + \frac + \frac \geq \frac = \frac = \frac + 1 \geq \frac (1) + 1 = \frac. \blacksquare
Example 2.
We have that \frac + \frac + \frac \geq \frac = \frac \geq \frac = \frac.
Example 3.
We have \frac + \frac \geq \frac so that a^4 + b^4 = \frac + \frac \geq \frac \geq \frac = \frac.
Example 4.
We have that \frac + \frac + \frac \geq \frac = \frac.
References
{{DEFAULTSORT:Sedrakyan's inequality
Inequalities
Linear algebra
Operator theory
Articles containing proofs
Mathematical analysis
Probabilistic inequalities>X, 2 / \operatorname \ge \operatorname 2 / \operatorname
Direct applications
Example 1. Nesbitt's inequality In mathematics, Nesbitt's inequality (mathematics), inequality states that for positive real numbers ''a'', ''b'' and ''c'',
:\frac+\frac+\frac\geq\frac.
It is an elementary special case (N = 3) of the difficult and much studied Shapiro inequality, ...
.
For positive real numbers a, b, c:
\frac + \frac + \frac \geq \frac.
Example 2. International Mathematical Olympiad
The International Mathematical Olympiad (IMO) is a mathematical olympiad for pre-university students, and is the oldest of the International Science Olympiads. The first IMO was held in Romania in 1959. It has since been held annually, except i ...
(IMO) 1995.
For positive real numbers a,b,c , where abc=1 we have that \frac+\frac+\frac \geq \frac.
Example 3.
For positive real numbers a,b we have that 8(a^4+b^4) \geq (a+b)^4.
Example 4.
For positive real numbers a,b,c we have that \frac+\frac+\frac \geq \frac.
Proofs
Example 1.
Proof: Use n = 3, \left(a_1, a_2, a_3\right) := (a, b, c), and \left(b_1, b_2, b_3\right) := (a(b + c), b(c + a), c(a + b)) to conclude: \frac + \frac + \frac \geq \frac = \frac = \frac + 1 \geq \frac (1) + 1 = \frac. \blacksquare
Example 2.
We have that \frac + \frac + \frac \geq \frac = \frac \geq \frac = \frac.
Example 3.
We have \frac + \frac \geq \frac so that a^4 + b^4 = \frac + \frac \geq \frac \geq \frac = \frac.
Example 4.
We have that \frac + \frac + \frac \geq \frac = \frac.
References
{{DEFAULTSORT:Sedrakyan's inequality
Inequalities
Linear algebra
Operator theory
Articles containing proofs
Mathematical analysis
Probabilistic inequalities>X, /math> and E /math> are both defined.
Then
\operatorname ^2/Y\ge \operatorname \ge_\operatorname 2___\operatorname <_math>
<h1><br>.html" ;"title="X, ]^2 / \operatorname \ge \operatorname 2 / \operatorname
Direct applications
Example 1. Nesbitt's inequality In mathematics, Nesbitt's inequality (mathematics), inequality states that for positive real numbers ''a'', ''b'' and ''c'',
:\frac+\frac+\frac\geq\frac.
It is an elementary special case (N = 3) of the difficult and much studied Shapiro inequality, ...
.
For positive real numbers a, b, c:
\frac + \frac + \frac \geq \frac.
Example 2. International Mathematical Olympiad
The International Mathematical Olympiad (IMO) is a mathematical olympiad for pre-university students, and is the oldest of the International Science Olympiads. The first IMO was held in Romania in 1959. It has since been held annually, except i ...
(IMO) 1995.
For positive real numbers a,b,c , where abc=1 we have that \frac+\frac+\frac \geq \frac.
Example 3.
For positive real numbers a,b we have that 8(a^4+b^4) \geq (a+b)^4.
Example 4.
For positive real numbers a,b,c we have that \frac+\frac+\frac \geq \frac.
Proofs
Example 1.
Proof: Use n = 3, \left(a_1, a_2, a_3\right) := (a, b, c), and \left(b_1, b_2, b_3\right) := (a(b + c), b(c + a), c(a + b)) to conclude: \frac + \frac + \frac \geq \frac = \frac = \frac + 1 \geq \frac (1) + 1 = \frac. \blacksquare
Example 2.
We have that \frac + \frac + \frac \geq \frac = \frac \geq \frac = \frac.
Example 3.
We have \frac + \frac \geq \frac so that a^4 + b^4 = \frac + \frac \geq \frac \geq \frac = \frac.
Example 4.
We have that \frac + \frac + \frac \geq \frac = \frac.
References
{{DEFAULTSORT:Sedrakyan's inequality
Inequalities
Linear algebra
Operator theory
Articles containing proofs
Mathematical analysis
Probabilistic inequalities>X, /math> and E /math> are both defined.
Then
\operatorname ^2/Y\ge \operatorname X, 2 / \operatorname \ge \operatorname 2 / \operatorname
Direct applications
Example 1. Nesbitt's inequality In mathematics, Nesbitt's inequality (mathematics), inequality states that for positive real numbers ''a'', ''b'' and ''c'',
:\frac+\frac+\frac\geq\frac.
It is an elementary special case (N = 3) of the difficult and much studied Shapiro inequality, ...
.
For positive real numbers a, b, c:
\frac + \frac + \frac \geq \frac.
Example 2. International Mathematical Olympiad
The International Mathematical Olympiad (IMO) is a mathematical olympiad for pre-university students, and is the oldest of the International Science Olympiads. The first IMO was held in Romania in 1959. It has since been held annually, except i ...
(IMO) 1995.
For positive real numbers a,b,c , where abc=1 we have that \frac+\frac+\frac \geq \frac.
Example 3.
For positive real numbers a,b we have that 8(a^4+b^4) \geq (a+b)^4.
Example 4.
For positive real numbers a,b,c we have that \frac+\frac+\frac \geq \frac.
Proofs
Example 1.
Proof: Use n = 3, \left(a_1, a_2, a_3\right) := (a, b, c), and \left(b_1, b_2, b_3\right) := (a(b + c), b(c + a), c(a + b)) to conclude: \frac + \frac + \frac \geq \frac = \frac = \frac + 1 \geq \frac (1) + 1 = \frac. \blacksquare
Example 2.
We have that \frac + \frac + \frac \geq \frac = \frac \geq \frac = \frac.
Example 3.
We have \frac + \frac \geq \frac so that a^4 + b^4 = \frac + \frac \geq \frac \geq \frac = \frac.
Example 4.
We have that \frac + \frac + \frac \geq \frac = \frac.
References
{{DEFAULTSORT:Sedrakyan's inequality
Inequalities
Linear algebra
Operator theory
Articles containing proofs
Mathematical analysis
Probabilistic inequalities>X, 2 / \operatorname \ge \operatorname 2 / \operatorname
Direct applications
Example 1. Nesbitt's inequality In mathematics, Nesbitt's inequality (mathematics), inequality states that for positive real numbers ''a'', ''b'' and ''c'',
:\frac+\frac+\frac\geq\frac.
It is an elementary special case (N = 3) of the difficult and much studied Shapiro inequality, ...
.
For positive real numbers a, b, c:
\frac + \frac + \frac \geq \frac.
Example 2. International Mathematical Olympiad
The International Mathematical Olympiad (IMO) is a mathematical olympiad for pre-university students, and is the oldest of the International Science Olympiads. The first IMO was held in Romania in 1959. It has since been held annually, except i ...
(IMO) 1995.
For positive real numbers a,b,c , where abc=1 we have that \frac+\frac+\frac \geq \frac.
Example 3.
For positive real numbers a,b we have that 8(a^4+b^4) \geq (a+b)^4.
Example 4.
For positive real numbers a,b,c we have that \frac+\frac+\frac \geq \frac.
Proofs
Example 1.
Proof: Use n = 3, \left(a_1, a_2, a_3\right) := (a, b, c), and \left(b_1, b_2, b_3\right) := (a(b + c), b(c + a), c(a + b)) to conclude: \frac + \frac + \frac \geq \frac = \frac = \frac + 1 \geq \frac (1) + 1 = \frac. \blacksquare
Example 2.
We have that \frac + \frac + \frac \geq \frac = \frac \geq \frac = \frac.
Example 3.
We have \frac + \frac \geq \frac so that a^4 + b^4 = \frac + \frac \geq \frac \geq \frac = \frac.
Example 4.
We have that \frac + \frac + \frac \geq \frac = \frac.
References
{{DEFAULTSORT:Sedrakyan's inequality
Inequalities
Linear algebra
Operator theory
Articles containing proofs
Mathematical analysis
Probabilistic inequalities>X, 2 / \operatorname \ge \operatorname 2 / \operatorname
Direct applications
Example 1. Nesbitt's inequality In mathematics, Nesbitt's inequality (mathematics), inequality states that for positive real numbers ''a'', ''b'' and ''c'',
:\frac+\frac+\frac\geq\frac.
It is an elementary special case (N = 3) of the difficult and much studied Shapiro inequality, ...
.
For positive real numbers a, b, c:
\frac + \frac + \frac \geq \frac.
Example 2. International Mathematical Olympiad
The International Mathematical Olympiad (IMO) is a mathematical olympiad for pre-university students, and is the oldest of the International Science Olympiads. The first IMO was held in Romania in 1959. It has since been held annually, except i ...
(IMO) 1995.
For positive real numbers a,b,c , where abc=1 we have that \frac+\frac+\frac \geq \frac.
Example 3.
For positive real numbers a,b we have that 8(a^4+b^4) \geq (a+b)^4.
Example 4.
For positive real numbers a,b,c we have that \frac+\frac+\frac \geq \frac.
Proofs
Example 1.
Proof: Use n = 3, \left(a_1, a_2, a_3\right) := (a, b, c), and \left(b_1, b_2, b_3\right) := (a(b + c), b(c + a), c(a + b)) to conclude: \frac + \frac + \frac \geq \frac = \frac = \frac + 1 \geq \frac (1) + 1 = \frac. \blacksquare
Example 2.
We have that \frac + \frac + \frac \geq \frac = \frac \geq \frac = \frac.
Example 3.
We have \frac + \frac \geq \frac so that a^4 + b^4 = \frac + \frac \geq \frac \geq \frac = \frac.
Example 4.
We have that \frac + \frac + \frac \geq \frac = \frac.
References
{{DEFAULTSORT:Sedrakyan's inequality
Inequalities
Linear algebra
Operator theory
Articles containing proofs
Mathematical analysis
Probabilistic inequalities>X, 2 / \operatorname \ge \operatorname 2 / \operatorname
Direct applications
Example 1.
Nesbitt's inequality In mathematics, Nesbitt's inequality (mathematics), inequality states that for positive real numbers ''a'', ''b'' and ''c'',
:\frac+\frac+\frac\geq\frac.
It is an elementary special case (N = 3) of the difficult and much studied Shapiro inequality, ...
.
For positive real numbers
a, b, c:
\frac + \frac + \frac \geq \frac.
Example 2.
International Mathematical Olympiad
The International Mathematical Olympiad (IMO) is a mathematical olympiad for pre-university students, and is the oldest of the International Science Olympiads. The first IMO was held in Romania in 1959. It has since been held annually, except i ...
(IMO) 1995.
For positive real numbers
a,b,c , where
abc=1 we have that
\frac+\frac+\frac \geq \frac.
Example 3.
For positive real numbers
a,b we have that
8(a^4+b^4) \geq (a+b)^4.
Example 4.
For positive real numbers
a,b,c we have that
\frac+\frac+\frac \geq \frac.
Proofs
Example 1.
Proof: Use
n = 3, \left(a_1, a_2, a_3\right) := (a, b, c), and
\left(b_1, b_2, b_3\right) := (a(b + c), b(c + a), c(a + b)) to conclude:
\frac + \frac + \frac \geq \frac = \frac = \frac + 1 \geq \frac (1) + 1 = \frac. \blacksquare
Example 2.
We have that
\frac + \frac + \frac \geq \frac = \frac \geq \frac = \frac.
Example 3.
We have
\frac + \frac \geq \frac so that
a^4 + b^4 = \frac + \frac \geq \frac \geq \frac = \frac.
Example 4.
We have that
\frac + \frac + \frac \geq \frac = \frac.
References
{{DEFAULTSORT:Sedrakyan's inequality
Inequalities
Linear algebra
Operator theory
Articles containing proofs
Mathematical analysis
Probabilistic inequalities