Motivation
When we are working in a normed space ''X'' and we have a sequence that converges weakly to , then a natural question arises. Does the sequence converge in perhaps a more desirable manner? That is, does the sequence converge to in norm? A canonical example of this property, and commonly used to illustrate the Schur property, is theDefinition
Suppose that we have a normed space (''X'', , , ·, , ), an arbitrary member of ''X'', and an arbitrary sequence in the space. We say that ''X'' has Schur's property if converging weakly to implies that . In other words, the weak and strong topologies share the same convergent sequences. Note however that weak and strong topologies are always distinct in infinite-dimensional space.Examples
The space ''ℓ1'' of sequences whose series is absolutely convergent has the Schur property.Name
This property was named after the early 20th century mathematician Issai Schur who showed that ''ℓ1'' had the above property in his 1921 paper.J. Schur, "Über lineare Transformationen in der Theorie der unendlichen Reihen", '' Journal für die reine und angewandte Mathematik'', 151 (1921) pp. 79-111See also
* Radon-Riesz property for a similar property of normed spaces * Schur's theoremNotes
References
* {{DEFAULTSORT:Schur's Property Functional analysis