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In mathematics, the Rabinowitsch trick, introduced by George Yuri Rainich and published under his original name , is a short way of proving the general case of the Hilbert Nullstellensatz from an easier special case (the so-called ''weak'' Nullstellensatz), by introducing an extra variable. The Rabinowitsch trick goes as follows. Let ''K'' be an algebraically closed field. Suppose the
polynomial In mathematics, a polynomial is an expression consisting of indeterminates (also called variables) and coefficients, that involves only the operations of addition, subtraction, multiplication, and positive-integer powers of variables. An ex ...
''f'' in ''K'' 'x''1,...''x''''n''vanishes whenever all polynomials ''f''1,....,''f''''m'' vanish. Then the polynomials ''f''1,....,''f''''m'', 1 − ''x''0''f'' have no common zeros (where we have introduced a new variable ''x''0), so by the weak Nullstellensatz for ''K'' 'x''0, ..., ''x''''n''they generate the unit ideal of ''K'' 'x''0 ,..., ''x''''n'' Spelt out, this means there are polynomials g_0,g_1,\dots,g_m \in K _0,x_1,\dots,x_n/math> such that : 1 = g_0(x_0,x_1,\dots,x_n) (1 - x_0 f(x_1,\dots,x_n)) + \sum_^m g_i(x_0,x_1,\dots,x_n) f_i(x_1,\dots,x_n) as an equality of elements of the polynomial ring K _0,x_1,\dots,x_n/math>. Since x_0,x_1,\dots,x_n are free variables, this equality continues to hold if expressions are substituted for some of the variables; in particular, it follows from substituting x_0 = 1/f(x_1,\dots,x_n) that : 1 = \sum_^m g_i(1/f(x_1,\dots,x_n),x_1,\dots,x_n) f_i(x_1,\dots,x_n) as elements of the field of rational functions K(x_1,\dots,x_n), the
field of fractions In abstract algebra, the field of fractions of an integral domain is the smallest field in which it can be embedded. The construction of the field of fractions is modeled on the relationship between the integral domain of integers and the field ...
of the polynomial ring K _1,\dots,x_n/math>. Moreover, the only expressions that occur in the denominators of the right hand side are ''f'' and powers of ''f'', so rewriting that right hand side to have a common denominator results in an equality on the form : 1 = \frac for some natural number ''r'' and polynomials h_1,\dots,h_m \in K _1,\dots,x_n/math>. Hence : f(x_1,\dots,x_n)^r = \sum_^m h_i(x_1,\dots,x_n) f_i(x_1,\dots,x_n), which literally states that f^r lies in the ideal generated by ''f''1,....,''f''''m''. This is the full version of the Nullstellensatz for ''K'' 'x''1,...,''x''''n''


References

* *{{citation, first=J.L., last= Rabinowitsch, title=Zum Hilbertschen Nullstellensatz, journal= Math. Ann. , volume= 102 , year=1929, issue=1, pages= 520, mr=1512592, doi=10.1007/BF01782361, language=de Commutative algebra