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In mathematics, lifting theory was first introduced by
John von Neumann John von Neumann ( ; ; December 28, 1903 – February 8, 1957) was a Hungarian and American mathematician, physicist, computer scientist and engineer. Von Neumann had perhaps the widest coverage of any mathematician of his time, in ...
in a pioneering paper from 1931, in which he answered a question raised by
Alfréd Haar Alfréd Haar (; 11 October 1885, Budapest – 16 March 1933, Szeged) was a Kingdom of Hungary, Hungarian mathematician. In 1904 he began to study at the University of Göttingen. His doctorate was supervised by David Hilbert. The Haar me ...
. The theory was further developed by Dorothy Maharam (1958) and by Alexandra Ionescu Tulcea and Cassius Ionescu Tulcea (1961). Lifting theory was motivated to a large extent by its striking applications. Its development up to 1969 was described in a monograph of the Ionescu Tulceas. Lifting theory continued to develop since then, yielding new results and applications.


Definitions

A lifting on a
measure space A measure space is a basic object of measure theory, a branch of mathematics that studies generalized notions of volumes. It contains an underlying set, the subsets of this set that are feasible for measuring (the -algebra) and the method that ...
(X, \Sigma, \mu) is a linear and multiplicative operator T : L^\infty(X, \Sigma, \mu) \to \mathcal^\infty(X, \Sigma, \mu) which is a right inverse of the quotient map \begin \mathcal L^\infty(X,\Sigma,\mu) \to L^\infty(X,\Sigma,\mu) \\ f \mapsto \end where \mathcal^\infty(X,\Sigma,\mu) is the seminormed Lp space of measurable functions and L^\infty(X, \Sigma, \mu) is its usual normed quotient. In other words, a lifting picks from every equivalence class /math> of bounded measurable functions modulo negligible functions a representative— which is henceforth written T( or T /math> or simply Tf — in such a way that T = 1 and for all p \in X and all r, s \in \Reals, T(r s (p) = rT p) + sT p), T( times (p) = T p) \times T p). Liftings are used to produce disintegrations of measures, for instance
conditional probability distribution In probability theory and statistics, the conditional probability distribution is a probability distribution that describes the probability of an outcome given the occurrence of a particular event. Given two jointly distributed random variables X ...
s given continuous random variables, and fibrations of Lebesgue measure on the level sets of a function.


Existence of liftings

Theorem. Suppose (X, \Sigma, \mu) is complete. Then (X, \Sigma, \mu) admits a lifting if and only if there exists a collection of mutually disjoint integrable sets in \Sigma whose union is X. In particular, if (X, \Sigma, \mu) is the completion of a ''σ''-finite measure or of an inner regular Borel measure on a
locally compact space In topology and related branches of mathematics, a topological space is called locally compact if, roughly speaking, each small portion of the space looks like a small portion of a compact space. More precisely, it is a topological space in which ...
, then (X, \Sigma, \mu) admits a lifting.
The proof consists in extending a lifting to ever larger sub-''σ''-algebras, applying Doob's martingale convergence theorem if one encounters a countable chain in the process.


Strong liftings

Suppose (X, \Sigma, \mu) is complete and X is equipped with a completely regular Hausdorff topology \tau \subseteq \Sigma such that the union of any collection of negligible open sets is again negligible – this is the case if (X, \Sigma, \mu) is ''σ''-finite or comes from a Radon measure. Then the ''support'' of \mu, \operatorname(\mu), can be defined as the complement of the largest negligible open subset, and the collection C_b(X, \tau) of bounded continuous functions belongs to \mathcal L^\infty(X, \Sigma, \mu). A strong lifting for (X, \Sigma, \mu) is a lifting T : L^\infty(X, \Sigma, \mu) \to \mathcal^\infty(X, \Sigma, \mu) such that T\varphi = \varphi on \operatorname(\mu) for all \varphi in C_b(X, \tau). This is the same as requiring that T U \geq (U \cap \operatorname(\mu)) for all open sets U in \tau.
Theorem. If (\Sigma, \mu) is ''σ''-finite and complete and \tau has a countable basis then (X, \Sigma, \mu) admits a strong lifting.
Proof. Let T_0 be a lifting for (X, \Sigma, \mu) and U_1, U_2, \ldots a countable basis for \tau. For any point p in the negligible set N := \bigcup\nolimits_n \left\ let T_p be any characterA ''character'' on a unital algebra is a multiplicative linear functional with values in the coefficient field that maps the unit to 1. on L^\infty(X, \Sigma, \mu) that extends the character \phi \mapsto \phi(p) of C_b(X, \tau). Then for p in X and /math> in L^\infty(X, \Sigma, \mu) define: (T (p):= \begin (T_0 (p)& p\notin N\\ T_p p\in N. \end T is the desired strong lifting.


Application: disintegration of a measure

Suppose (X, \Sigma, \mu) and (Y, \Phi, \nu) are ''σ''-finite measure spaces (\mu, \nu positive) and \pi : X \to Y is a measurable map. A disintegration of \mu along \pi with respect to \nu is a slew Y \ni y \mapsto \lambda_y of positive ''σ''-additive measures on (\Sigma, \mu) such that #\lambda_y is carried by the fiber \pi^(\) of \pi over y, i.e. \ \in \Phi and \lambda_y\left((X\setminus \pi^(\)\right) = 0 for almost all y \in Y #for every \mu-integrable function f,\int_X f(p)\;\mu(dp)= \int_Y \left(\int_ f(p)\,\lambda_y(dp)\right) \nu(dy) \qquad (*) in the sense that, for \nu-almost all y in Y, f is \lambda_y-integrable, the function y \mapsto \int_ f(p)\,\lambda_y(dp) is \nu-integrable, and the displayed equality (*) holds. Disintegrations exist in various circumstances, the proofs varying but almost all using strong liftings. Here is a rather general result. Its short proof gives the general flavor.
Theorem. Suppose X is a Polish space and Y a separable Hausdorff space, both equipped with their Borel ''σ''-algebras. Let \mu be a ''σ''-finite Borel measure on X and \pi : X \to Y a \Sigma, \Phi-measurable map. Then there exists a σ-finite Borel measure \nu on Y and a disintegration (*). If \mu is finite, \nu can be taken to be the pushforward \pi_* \mu, and then the \lambda_y are probabilities.
Proof. Because of the polish nature of X there is a sequence of compact subsets of X that are mutually disjoint, whose union has negligible complement, and on which \pi is continuous. This observation reduces the problem to the case that both X and Y are compact and \pi is continuous, and \nu = \pi_* \mu. Complete \Phi under \nu and fix a strong lifting T for (Y, \Phi, \nu). Given a bounded \mu-measurable function f, let \lfloor f\rfloor denote its conditional expectation under \pi, that is, the Radon-Nikodym derivative off \mu is the measure that has density f with respect to \mu \pi_*(f \mu) with respect to \pi_* \mu. Then set, for every y in Y, \lambda_y(f) := T(\lfloor f\rfloor)(y). To show that this defines a disintegration is a matter of bookkeeping and a suitable Fubini theorem. To see how the strongness of the lifting enters, note that \lambda_y(f \cdot \varphi \circ \pi) = \varphi(y) \lambda_y(f) \qquad \forall y\in Y, \varphi \in C_b(Y), f \in L^\infty(X, \Sigma, \mu) and take the infimum over all positive \varphi in C_b(Y) with \varphi(y) = 1; it becomes apparent that the support of \lambda_y lies in the fiber over y.


References

{{Measure theory Measure theory