Proof
This is Utumi's argument as it appears in ;Lemma Assume that ''R'' satisfies the ascending chain condition on annihilators of the form where ''a'' is in ''R''. Then # Any nil one-sided ideal is contained in the lower nil radical Nil*(''R''); # Every nonzero nil right ideal contains a nonzero nilpotent right ideal. # Every nonzero nil left ideal contains a nonzero nilpotent left ideal. ;Levitzki's Theorem Let ''R'' be a right Noetherian ring. Then every nil one-sided ideal of ''R'' is nilpotent. In this case, the upper and lower nilradicals are equal, and moreover this ideal is the largest nilpotent ideal among nilpotent right ideals and among nilpotent left ideals. ''Proof'': In view of the previous lemma, it is sufficient to show that the lower nilradical of ''R'' is nilpotent. Because ''R'' is right Noetherian, a maximal nilpotent ideal ''N'' exists. By maximality of ''N'', the quotient ring ''R''/''N'' has no nonzero nilpotent ideals, so ''R''/''N'' is a semiprime ring. As a result, ''N'' contains the lower nilradical of ''R''. Since the lower nilradical contains all nilpotent ideals, it also contains ''N'', and so ''N'' is equal to the lower nilradical.See also
* Nilpotent ideal * Köthe conjecture * Jacobson radicalNotes
References
* * * * * * {{DEFAULTSORT:Levitzky's Theorem Theorems in ring theory