Description
When a new request arrives while the drive is idle, the initial arm/head movement will be in the direction of the cylinder where the data is stored, either ''in'' or ''out''. As additional requests arrive, requests are serviced only in the current direction of arm movement until the arm reaches the edge of the disk. When this happens, the direction of the arm reverses, and the requests that were remaining in the opposite direction are serviced, and so on.{{cite web , url=http://www.dcs.ed.ac.uk/home/stg/pub/D/disk.html , title=Disk scheduling , accessdate=2008-01-21 , archiveurl = https://web.archive.org/web/20080606005055/http://www.dcs.ed.ac.uk/home/stg/pub/D/disk.html , archivedate = 2008-06-06Variations
One variation of this method ensures all requests are serviced in only one direction, that is, once the head has arrived at the outer edge of the disk, it returns to the beginning and services the new requests in this one direction only (or vice versa). This is known as the "Circular Elevator Algorithm" or C-SCAN. Although the time of the return seek is wasted, this results in more equal performance for all head positions, as the expected distance from the head is always half the maximum distance, unlike in the standard elevator algorithm where cylinders in the middle will be serviced as much as twice as often as the innermost or outermost cylinders. Other variations include: *Example
The following is an example of how to calculate average disk seek times for both the SCAN and C-SCAN algorithms. * Example list of pending disk requests (listed by track number): 100, 50, 10, 20, 75. * The starting track number for the examples will be 35. * The list will need to be sorted in ascending order: 10, 20, 50, 75, 100. Both SCAN and C-SCAN behave in the same manner until they reach the last track queued. For the sake of this example let us assume that the SCAN algorithm is currently going from a lower track number to a higher track number (like the C-SCAN is doing). For both methods, one takes the difference in magnitude (i.e. absolute value) between the next track request and the current track. * Seek 1: 50 − 35 = 15 * Seek 2: 75 − 50 = 25 * Seek 3: 100 − 75 = 25 At this point both have reached the highest (end) track request. SCAN will just reverse direction and service the next closest disk request (in this example, 20) and C-SCAN will always go back to track 0 and start going to higher track requests. * Seek 4 (SCAN): 20 − 100 = 80 * Seek 5 (SCAN): 10 − 20 = 10 * Total (SCAN): 155 * Average (SCAN): 155 ÷ 5 = 31 * Seek 4 (C-SCAN): 0 − 100 = 0 head movement as cylinders are treated as a circular list (C-SCAN always goes back to the first track) * Seek 5 (C-SCAN): 10 − 0 = 10 * Seek 6 (C-SCAN): 20 − 10 = 10 * Total (C-SCAN): 85 * Average (C-SCAN): 85 ÷ 5 = 17 Even though six seeks were performed using the C-SCAN algorithm, only five I/Os were actually done.Analysis
For both versions of the elevator algorithm, the arm movement is less than twice the number of total cylinders and produces a smaller variance in response time. The algorithm is also relatively simple. The elevator algorithm is not always better thanSee also
* FCFS *References