Hierarchy and classification
According to ''Java Language Specification'': *A type variable is an unqualified identifier. Type variables are introduced by generic class declarations, generic interface declarations, generic method declarations, and by generic constructor declarations. *A class is generic if it declares one or more type variables. These type variables are known as the type parameters of the class. It defines one or more type variables that act as parameters. A generic class declaration defines a set of parameterized types, one for each possible invocation of the type parameter section. All of these parameterized types share the same class at runtime. *An interface is generic if it declares one or more type variables. These type variables are known as the type parameters of the interface. It defines one or more type variables that act as parameters. A generic interface declaration defines a set of types, one for each possible invocation of the type parameter section. All parameterized types share the same interface at runtime. *A method is generic if it declares one or more type variables. These type variables are known as the formal type parameters of the method. The form of the formal type parameter list is identical to a type parameter list of a class or interface. *A constructor can be declared as generic, independently of whether the class that the constructor is declared in is itself generic. A constructor is generic if it declares one or more type variables. These type variables are known as the formal type parameters of the constructor. The form of the formal type parameter list is identical to a type parameter list of a generic class or interface.Motivation
The following block of Java code illustrates a problem that exists when not using generics. First, it declares anArrayList
of type Object
. Then, it adds a String
to the ArrayList
. Finally, it attempts to retrieve the added String
and cast it to an Integer
—an error in logic, as it is not generally possible to cast an arbitrary string to an integer.
java.lang.ClassCastException
) when executing the third line of code. This type of logic error can be detected during compile time by using generics and is the primary motivation for using them.
The above code fragment can be rewritten using generics as follows:
String
within the angle brackets declares the ArrayList
to be constituted of String
(a descendant of the ArrayList
's generic Object
constituents). With generics, it is no longer necessary to cast the third line to any particular type, because the result of v.get(0)
is defined as String
by the code generated by the compiler.
The logical flaw in the third line of this fragment will be detected as a compile-time error (with J2SE 5.0 or later) because the compiler will detect that v.get(0)
returns String
instead of Integer
. For a more elaborate example, see reference.
Here is a small excerpt from the definition of the interfaces List
and Iterator
in package :
Type wildcards
A type argument for a parameterized type is not limited to a concrete class or interface. Java allows the use of ''type wildcards'' to serve as type arguments for parameterized types. Wildcards are type arguments in the form ">
"; optionally with an upper or lower bound. Given that the exact type represented by a wildcard is unknown, restrictions are placed on the type of methods that may be called on an object that uses parameterized types.
Here is an example where the element type of a Collection
is parameterized by a wildcard:
c
stands for, we cannot add objects to it. The add()
method takes arguments of type E
, the element type of the Collection
generic interface. When the actual type argument is ?
, it stands for some unknown type. Any method argument value we pass to the add()
method would have to be a subtype of this unknown type. Since we don't know what type that is, we cannot pass anything in. The sole exception is null; which is a member of every type.
To specify the extends
keyword is used to indicate that the type argument is a subtype of the bounding class. So List<? extends Number>
means that the given list contains objects of some unknown type which extends the Number
class. For example, the list could be List<Float>
or List<Number>
. Reading an element from the list will return a Number
. Adding null elements is, again, also allowed.
The use of wildcards above adds flexibility since there is not any inheritance relationship between any two parameterized types with concrete type as type argument. Neither List
nor List
is a subtype of the other; even though Integer
is a subtype of Number
. So, any method that takes List
as a parameter does not accept an argument of List
. If it did, it would be possible to insert a Number
that is not an Integer
into it; which violates type safety. Here is an example that demonstrates how type safety would be violated if List
were a subtype of List
:
super
keyword is used. This keyword indicates that the type argument is a supertype of the bounding class. So, List<? super Number>
could represent List<Number>
or List<Object>
. Reading from a list defined as List<? super Number>
returns elements of type Object
. Adding to such a list requires either elements of type Number
, any subtype of Number
or null (which is a member of every type).
The mnemonic PECS (Producer Extends, Consumer Super) from the book Effective Java by Joshua Bloch gives an easy way to remember when to use wildcards (corresponding to Generic class definitions
Here is an example of a generic Java class, which can be used to represent individual entries (key to value mappings) in a map:grade: (Mike, A) mark: (Mike, 100) 13 is prime.
Diamond operator
Thanks to type inference, Java SE 7 and above allow the programmer to substitute an empty pair of angle brackets (<>
, called the ''diamond operator'') for a pair of angle brackets containing the one or more type parameters that a sufficiently-close context implies. Thus, the above code example using Entry
can be rewritten as:
Generic method definitions
Here is an example of a generic method using the generic class above:
in the above method, we will get compilation error (cannot find symbol 'Type') since it represents the declaration of the symbol.
In many cases the user of the method need not indicate the type parameters, as they can be inferred:
Generics in throws clause
Although exceptions themselves cannot be generic, generic parameters can appear in a throws clause:Problems with type erasure
Generics are checked at compile-time for type-correctness. The generic type information is then removed in a process called type erasure. For example,List<Integer>
will be converted to the non-generic type List
, which ordinarily contains arbitrary objects. The compile-time check guarantees that the resulting code is type-correct.
Because of type erasure, type parameters cannot be determined at run-time. For example, when an ArrayList
is examined at runtime, there is no general way to determine whether, before type erasure, it was an ArrayList<Integer>
or an ArrayList<Float>
. Many people are dissatisfied with this restriction. There are partial approaches. For example, individual elements may be examined to determine the type they belong to; for example, if an ArrayList
contains an Integer
, that ArrayList may have been parameterized with Integer
(however, it may have been parameterized with any parent of Integer
, such as Number
or Object
).
Demonstrating this point, the following code outputs "Equal":
Project on generics
Project Valhalla is an experimental project to incubate improved Java generics and language features, for future versions potentially from Java 10 onwards. Potential enhancements include: * generic specialization, e.g. ListSee also
*References