Directional Derivative

In mathematics, the directional derivative of a multivariable differentiable (scalar) function along a given vector v at a given point x intuitively represents the instantaneous rate of change of the function, moving through x with a velocity specified by v.

The directional derivative of a scalar function ''f'' with respect to a vector v at a point (e.g., position) x may be denoted by any of the following:
$\nabla_(\mathbf)=f'_\mathbf(\mathbf)=D_\mathbff(\mathbf)=Df(\mathbf)(\mathbf)=\partial_\mathbff(\mathbf)=\mathbf\cdot=\mathbf\cdot \frac.$

It therefore generalizes the notion of a partial derivative, in which the rate of change is taken along one of the curvilinear coordinate curves, all other coordinates being constant.
The directional derivative is a special case of the Gateaux derivative.

Definition

The ''directional derivative'' of a scalar function
:$f(\mathbf) = f(x_1, x_2, \ldots, x_n)$
along a vector
:$\mathbf = (v_1, \ldots, v_n)$
is the function $\nabla_$ defined by the limit
:$\nabla_(\mathbf) = \lim_.$

This definition is valid in a broad range of contexts, for example where the norm of a vector (and hence a unit vector) is undefined.

For differentiable functions

If the function ''f'' is differentiable at x, then the directional derivative exists along any unit
vector v at x, and one has

:$\nabla_(\mathbf) = \nabla f(\mathbf) \cdot \mathbf$

where the $\nabla$ on the right denotes the ''gradient'', $\cdot$ is the dot product and v is a unit vector. This follows from defining a path $h(t)=x+tv$ and using the definition of the derivative as a limit which can be calculated along this path to get:

:$\begin 0&=\lim_\frac t \\ &=\lim_\frac t - Df(x)(v) \\ &=\nabla_v f(x)-Df(x)(v). \end$

Intuitively, the directional derivative of ''f'' at a point x represents the rate of change of ''f'', in the direction of v with respect to time, when moving past x.

Using only direction of vector

The angle ''α'' between the tangent ''A'' and the horizontal will be maximum if the cutting plane contains the direction of the gradient ''A''.
In a Euclidean space, some authors define the directional derivative to be with respect to an arbitrary nonzero vector v after normalization, thus being independent of its magnitude and depending only on its direction.

This definition gives the rate of increase of ''f'' per unit of distance moved in the direction given by v. In this case, one has
:$\nabla_(\mathbf) = \lim_,$
or in case ''f'' is differentiable at x,
:$\nabla_(\mathbf) = \nabla f(\mathbf) \cdot \frac .$

Restriction to a unit vector

In the context of a function on a Euclidean space, some texts restrict the vector v to being a unit vector. With this restriction, both the above definitions are equivalent.

Properties

Many of the familiar properties of the ordinary derivative hold for the directional derivative. These include, for any functions ''f'' and ''g'' defined in a neighborhood of, and differentiable at, p:

# sum rule: $\nabla_ (f + g) = \nabla_ f + \nabla_ g.$
# constant factor rule: For any constant ''c'', $\nabla_ (cf) = c\nabla_ f.$
# product rule (or Leibniz's rule): $\nabla_ (fg) = g\nabla_ f + f\nabla_ g.$
# chain rule: If ''g'' is differentiable at p and ''h'' is differentiable at ''g''(p), then $\nabla_(h\circ g)(\mathbf) = h'(g(\mathbf)) \nabla_ g (\mathbf).$

In differential geometry

Let be a differentiable manifold and a point of . Suppose that is a function defined in a neighborhood of , and differentiable at . If is a tangent vector to at , then the directional derivative of along , denoted variously as (see Exterior derivative), $\nabla_ f(\mathbf)$ (see Covariant derivative), $L_ f(\mathbf)$ (see Lie derivative), or $_(f)$ (see ), can be defined as follows. Let be a differentiable curve with and . Then the directional derivative is defined by
:$\nabla_ f(\mathbf) = \left.\frac f\circ\gamma(\tau)\_.$
This definition can be proven independent of the choice of , provided is selected in the prescribed manner so that .

The Lie derivative

The Lie derivative of a vector field $W^\mu(x)$ along a vector field $V^\mu(x)$ is given by the difference of two directional derivatives (with vanishing torsion):
:$\mathcal_V W^\mu=(V\cdot\nabla) W^\mu-(W\cdot\nabla) V^\mu.$
In particular, for a scalar field $\phi(x)$, the Lie derivative reduces to the standard directional derivative:
:$\mathcal_V \phi=(V\cdot\nabla) \phi.$

The Riemann tensor

Directional derivatives are often used in introductory derivations of the Riemann curvature tensor. Consider a curved rectangle with an infinitesimal vector $\delta$ along one edge and $\delta'$ along the other. We translate a covector $S$ along $\delta$ then $\delta'$ and then subtract the translation along $\delta'$ and then $\delta$. Instead of building the directional derivative using partial derivatives, we use the covariant derivative. The translation operator for $\delta$ is thus
:$1+\sum_\nu \delta^\nu D_\nu=1+\delta\cdot D,$
and for $\delta'$,
:$1+\sum_\mu \delta'^\mu D_\mu=1+\delta'\cdot D.$
The difference between the two paths is then
:(1+\delta'\cdot D)(1+\delta\cdot D)S^\rho-(1+\delta\cdot D)(1+\delta'\cdot D)S^\rho=\sum_\delta'^\mu \delta^\nu _\mu,D_\nu_\rho.
It can be argued that the noncommutativity of the covariant derivatives measures the curvature of the manifold:
: _\mu,D_\nu_\rho=\pm \sum_\sigma R^\sigma_S_\sigma,
where $R$ is the Riemann curvature tensor and the sign depends on the sign convention of the author.

In group theory

Translations

In the Poincaré algebra, we can define an infinitesimal translation operator P as
:$\mathbf=i\nabla.$
(the ''i'' ensures that P is a self-adjoint operator) For a finite displacement λ, the unitary Hilbert space representation for translations is
:$U(\boldsymbol)=\exp\left(-i\boldsymbol\cdot\mathbf\right).$
By using the above definition of the infinitesimal translation operator, we see that the finite translation operator is an exponentiated directional derivative:
:$U(\boldsymbol)=\exp\left(\boldsymbol\cdot\nabla\right).$
This is a translation operator in the sense that it acts on multivariable functions ''f''(x) as
:$U(\boldsymbol) f(\mathbf)=\exp\left(\boldsymbol\cdot\nabla\right) f(\mathbf) = f(\mathbf+\boldsymbol).$

Rotations

The rotation operator also contains a directional derivative. The rotation operator for an angle ''θ'', i.e. by an amount ''θ'' = , ''θ'', about an axis parallel to $\hat = \boldsymbol/\theta$ is
:$U(R(\mathbf))=\exp(-i\mathbf\cdot\mathbf).$
Here L is the vector operator that generates SO(3):
:$\mathbf=\begin 0& 0 & 0\\ 0& 0 & 1\\ 0& -1 & 0 \end\mathbf+\begin 0 &0 & -1\\ 0& 0 &0 \\ 1 & 0 & 0 \end\mathbf+\begin 0&1 &0 \\ -1&0 &0 \\ 0 & 0 & 0 \end\mathbf.$
It may be shown geometrically that an infinitesimal right-handed rotation changes the position vector x by
:$\mathbf\rightarrow \mathbf-\delta\boldsymbol\times\mathbf.$
So we would expect under infinitesimal rotation:
:$U(R(\delta\boldsymbol)) f(\mathbf) = f(\mathbf-\delta\boldsymbol\times\mathbf)=f(\mathbf)-(\delta\boldsymbol\times\mathbf)\cdot\nabla f.$
It follows that
:$U(R(\delta\mathbf))=1-(\delta\mathbf\times\mathbf)\cdot\nabla.$
Following the same exponentiation procedure as above, we arrive at the rotation operator in the position basis, which is an exponentiated directional derivative:
:$U(R(\mathbf))=\exp(-(\mathbf\times\mathbf)\cdot\nabla).$

Normal derivative

A normal derivative is a directional derivative taken in the direction normal (that is, orthogonal) to some surface in space, or more generally along a normal vector field orthogonal to some hypersurface. See for example Neumann boundary condition. If the normal direction is denoted by $\mathbf$, then the normal derivative of a function ''f'' is sometimes denoted as $\frac$. In other notations,
\frac = \nabla f(\mathbf) \cdot \mathbf = \nabla_(\mathbf) = \frac \cdot \mathbf = Df(\mathbf) mathbf

In the continuum mechanics of solids

Several important results in continuum mechanics require the derivatives of vectors with respect to vectors and of tensors with respect to vectors and tensors.J. E. Marsden and T. J. R. Hughes, 2000, ''Mathematical Foundations of Elasticity'', Dover. The directional directive provides a systematic way of finding these derivatives.

See also

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Notes

References

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External links

Directional derivatives
at MathWorld.
Directional derivative
at PlanetMath.

{{Calculus topics

Differential calculus
Differential geometry
Generalizations of the derivative
Multivariable calculus
Scalars
Rates